Question

What is the difference of the rational expressions below? 6x - 1/ 2x^2 - 3/x

Answer 1

$-x/2x^3$

$-1/2x^2$

Answer 2

The required difference is $\frac{12x^3-1-6x}{2x^2}$

The given expression is,

$6x-\frac{1}{2x^2} -\frac{3}{x}$

Taking LCM $2x^2$

$6x-\frac{1}{2x^2} -\frac{3}{x} =\frac{12x^3-1-6x}{2x^2}$

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