It takes 24 h to fill a large basin

with two hoses, where the water

in one hose flows four times as

fast as the other hose. How long

will it take the slower hose to fill

the basin if the faster hose is not

functioning?

Respuesta :

Answer:

The answer is 72 hrs or 60 hrs

Step-by-step explanation:

Im not sure whether the answer is right. So you guys are gonna have to guess. :)

It will take 30 hours for the slower hose to fill  the basin if the faster hose is not  functioning.

Given that,

It takes 24 hours to fill a large basin  with two hoses,

Where the water  in one hose flows four times as  fast as the other hose.

We have to determine,

How long  will it take the slower hose to fill  the basin if the faster hose is not  functioning?

According to the question,

Let, the time taken by the faster hose to fill the pool be x hours.

Since a faster hose is 4 times faster than a slower hose so the time taken by a slower hose will be = 4x (It will take more time since it is slower)

Therefore, The equation can be written as,

[tex]\dfrac{1}{x} + \dfrac{1}{4x} = \dfrac{1}{24}\\\\\dfrac{4+1}{4x} = \dfrac{1}{24}\\\\\dfrac{5}{4x} = \dfrac{1}{24}\\\\4x = 5 \times 24\\\\4x = 120 \\\\x = \dfrac{120}{4}\\\\x = 30 \ hours[/tex]

Hence, It will take 30 hours for the slower hose to fill  the basin if the faster hose is not  functioning.

To know more about the Linear equation click the link given below.

https://brainly.com/question/13760328