Question

find the axis of symmetry for this parabola y=-2x^2-4x-11
write your answer as an equation

Answer 1

Answer:

x = - 1

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 ) , then the equation of the axis of symmetry is

x = - $\frac{b}{2a}$

y = - 2x² - 4x - 11 ← is in standard form

with a = - 2 and b = - 4 , thus

x = - $\frac{-4}{-4}$ = - 1

x = - 1 is the equation of the axis of symmetry