Answer:
First number = 25
Second number = 14
Step-by-step explanation:
Let the numbers be x & y
The sum of twice the first and thrice the second is 92
2x + 3y = 92 -------------------(I)
Four times the first exceeds seven times the second by 2
4x - 7y = 2 --------------------(II)
Multiply equation (I) by -2 and then add the equations
(I)*-2 -4x - 6y = -184
(II) 4x - 7y = 2 { Now add, thus x will be eliminated}
- 13y = -182 {Divide both sides by -13}
y = -182/-13
y = 14
Plugin the value of y in equation (I)
2x + 3*14 = 92
2x + 42 = 92
2x = 92 - 42
2x = 50
x = 50/2
x = 25
First number = 25
Second number = 14
