Question

Find the smallest square number that is divisible by each of the numbers 8, 9 and 10

Answer 1

Answer:

Step-by-step explanation:

Find the LCM of 8,9 and 10.

Prime Factorization to find LCM,

8 = 2 × 2 × 2

9 = 3 × 3

10 = 2 × 5

LCM ( 8 , 9 , 10 ) = 2 × 2 × 2 × 3 × 3 × 5 =360

But 360 is not square

Now we make the pairs complete by multiplying same numbers in prime factorization of LCM.

We need one 2 and one 5 to complete the pair.

We get, Least Square number = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600

Hope this helps

good Luck

Answer 2

Answer:

Step-by-step explanation:

Find Least common  denominator of 8, 9 & 10

8 = 2 * 2 * 2

9 = 3* 3

10 = 5*2

LCM = 2*2*2*3*3*5 = 8 * 9 * 5 = 360

To make 360 a perfect square,multiply by 10

360*10 = 3600 is a perfect square