The mean age of the employees at a large corporation is 35.2 years, and the standard deviation is 9.5 years. A random sample of 4 employees will be selected. What are the mean and standard deviation of the sampling distribution of the sample mean for samples of size 4 ? A. The mean is 35.2, and the standard deviation is 9.5. B. The mean is 35.2, and the standard deviation is 9.5/4. C. The mean is 35.2, and the standard deviation is 9.5/2. D. The mean is 35.2/4, and the standard deviation is 9.5/4. E. The mean is 35.2/2, and the standard deviation is 9.5/2.

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Answer:

c. The mean is 35.2, and the standard deviation is 9.5/2

Explanation:

fichoh

Using the central limit theorem, the mean and standard deviation of the sampling distribution are 35.2 and 9.5/2 respectively.

  • The mean of a sampling distribution according to the central limit theorem is equal to the mean of the population. Hence, mean of sampling distribution is 35.2

Standard deviation of sampling distribution :

  • [tex] \frac{σ}{\sqrt{n}}[/tex]

Hence,

  • Standard deviation = [tex] \frac{9.5}{\sqrt{4}} = \frac{9.5}{2}[/tex]

Hence, the standard deviation of sampling distribution is 9.5/2

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