After creating a Beer's Law plot using standard solutions of Q, you determined the slope of Beer's Law to be 0.598 M-1. Your unknown solution of Q tested had an absorbance of 0.148. Determine the concentration (in molarity) of the unknown solution.

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Answer:

[tex]C=0.247~M[/tex]

Explanation:

We have to start this question with Beer's Law, [tex]A=E*b*C*[/tex]. On this equation we will have:

A=Absorbance

E=Molar absorption coefficient

b= Optical path

C=Concentration

So, the question is: what values of this equation we know?. If we check the question we have the absorbance value "0.148" additionally we have the slope of the plot, this slope is the molar absorption coefficient, therefore E=0.598 M-1, finally we have also the optical path. The optical path is 1 cm for all devices, so b=1 cm. With all these values we can calculate the concentration "C".

[tex]C=\frac{A}{b*E}[/tex]

[tex]C=\frac{0.148}{1*0.598}[/tex]

[tex]C=0.247~M[/tex]

So, we will have a concentration of 0.247 M

I hope it helps!

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