Question

In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70×10−3s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball?

Answer 1

Answer:

J = 8.4 kg*m/s

Explanation:

The magnitude of the impulse, J, on the ball can be calculated using the following equation:

$J = F*t$   (1)

Where:

F: is the force = 12000 N

t: is the time = 0.70x10⁻³ s

So, by entering the values above into equation (1) we can find the impulse on the ball:

$J = F*t = 12000 N*0.70 \cdot 10^{-3} s = 8.4 kg*m/s$

Therefore, the impulse on the ball is 8.4 kg*m/s.

I hope it helps you!

Answer 2

The magnitude J of the impulse on the ball is 8.4 kg m/s.

Calculation of the impulse:

Since it applies a force of 12,000 N to the ball for a time of 0.70×10−3s.

So,

The magnitude is

$= Force \times time\\\\= 12,000 \times 0.70\times 10^{-3}$

= 8.4 kg m/s

Here we basically multiplied the force with the time to determine the magnitude.

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