Question

A 35 g steel ball is held by a ceiling-mounted electromagnet 3.5 m above the floor. A compressed-air cannon sits on the floor, 4.0 m to one side of the point directly under the ball. When a button is pressed, the ball drops and, simultaneously, the cannon fires a 25 g plastic ball. The two balls collide 1.0 m above the floor. What was the launch speed of the plastic ball

Answer 1

Answer:

8.95 m/s

Explanation:

(3.5-1.0) x 2 = gt²

t = √5/9.8 = 0.714 sec  

$V_x$ = X/t = 4/ 0.714 = 5.602 m/s

vertical velocity means it has to rise 1.0 m against gravity in 0.714s

$V_o_y$ = gt = 9.8 x 0.714 = 6.99 m/s

V = √$V_o_y$²+$V_x$ ² = √6.99²+5.602² = 8.95 m/s