Question

Jar A contains four liters of a solution that is 45% acid. Jar B contains five liters of a solution that is 48% acid. Jar C contains one liter of a solution that is k % acid. From jar C, 2/3 liters of the solution is added to jar A, and the remainder of the solution in jar C is added to jar B. At the end both jar A and jar B contain solutions that are 50% acid. Find k.

Answer 1

Answer:

k = 79%

Step-by-step explanation:

Jar A - 45% acid and 55% water - "a" liters

Jar B - 48% acid and 52% water - "b" liters

Jar C - k% acid and (100% - k%) water - "c" liters

0,45 . 4 = 1,8 l acid jar A

0,48 . 5 = 2,4 l acid jar B

2/3 + 4 = a ----> a = 14/3 liters

1/3 + 5 = b -----> b = 16/3 liters

14/3 * 50% = 14/6 = 7/3 acid jar A = 2,33 l acid jar A

16/3 * 50% = 16/6 = 8/3 acid jar B = 2,66 l acid jar B

2,33 - 1,8 =  0,53 add in jar A

2,66 - 2,4 = 0,26 add in jar B

0,53 + 0,26 = 0,79 liters acid jar C

1 - 0,79 = 0,21 liters water jar C

(0,79/1) * 100% = 79% acid in jar C

So: k% acid is 79%