Answer:
[tex]1.2*10^{-2} g[/tex]
Explanation:
[tex]1 mol - 6*10^{23} particles[/tex]
[tex]1.6*10^{20}* \frac{1 mol}{6.02*10^{23}} = 0.00026578 mol\\\\M(CO2) = 12 + 2*32=44 \frac{g}{mol}\\[/tex]
[tex]44\frac{g}{mol} *0.00026578 mol =0.012 = 1.2*10^{-2} g[/tex]
The mass of 1.6x[tex]10^{20}[/tex] molecules of carbon dioxide will be 1.2 × [tex]10^{-2}[/tex] g.
A physical body's mass would be its total amount of matter. Inertia, or even the body's resistance to acceleration whenever a net force will be applied, is also measured by this term.
Calculation of mass :
Given data:
Number of molecule of carbon -dioxide = 1.6x[tex]10^{20}[/tex].
It is known that , 1 mol = 6 × [tex]10^{23}[/tex] particle.
Since, 1.2 × [tex]10^{-2}[/tex] g × 1 mol / 6 × [tex]10^{23}[/tex] = 0.00026578 mol.
M([tex]CO_{2}[/tex]) = 12 +2 × 32 = 44 g/mol
Now, convert g/mol into gram.
44 g/mol × 0.000265 mol.= 0.012 = 1.2 × [tex]10^{-2}[/tex] g.
Therefore, the mass of carbon dioxide will be 1.2 × [tex]10^{-2}[/tex] g.
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