Answer:
k₁ = 2πf₁/v
k₂ = 2πf₂/v
Explanation:
Since the de Broglie relation λ=h/p (1 ) and momentum, p =kℏ (2)
From (1) p = h/λ = kℏ
So, h/λ = kℏ
Hence, k = h/ℏλ since ℏ = h/2π and wavelength, λ = v/f, substituting these two into k, we have
k = h/[(h/2π)(v/f)]
k = 2πf/v where k = wave number, f = frequency of wave and v = velocity of wave.
Now, for the first wave number k₁, k₁ = 2πf₁/v
for the second wave number k₂, k₂ = 2πf₂/v