Respuesta :

Answer:

[tex]35.86~g~H_2O[/tex]

Explanation:

In this case, we have to remember that relationship between the avogadro's number and the "mol" concept:

[tex]1~mol=6.023x10^2^3~molcules[/tex]

With this in mind, we can do the first conversion:

[tex]1.20x10^2^4~molecules~of~H_2O\frac{1~mol_H_2O}{6.023x10^2^3~molcules~of~H_2O}=1.99~mol_H_2O[/tex]

Now, if we calculate the molar mass of [tex]H_2O[/tex]. The atomic mass of O is 16 g/mol and the atomic mass of H is 1 g/mol, so:

(16*1)+(1*2)= 18 g/mol

In other words, [tex]1~mol~H_2O=~18~g~H_2O[/tex], so:

[tex]1.99~mol_H_2O\frac{18~g~H_2O}{1~mol~H_2O}=35.86~g~H_2O[/tex]

I hope it helps!

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