Answer:
[tex]35.86~g~H_2O[/tex]
Explanation:
In this case, we have to remember that relationship between the avogadro's number and the "mol" concept:
[tex]1~mol=6.023x10^2^3~molcules[/tex]
With this in mind, we can do the first conversion:
[tex]1.20x10^2^4~molecules~of~H_2O\frac{1~mol_H_2O}{6.023x10^2^3~molcules~of~H_2O}=1.99~mol_H_2O[/tex]
Now, if we calculate the molar mass of [tex]H_2O[/tex]. The atomic mass of O is 16 g/mol and the atomic mass of H is 1 g/mol, so:
(16*1)+(1*2)= 18 g/mol
In other words, [tex]1~mol~H_2O=~18~g~H_2O[/tex], so:
[tex]1.99~mol_H_2O\frac{18~g~H_2O}{1~mol~H_2O}=35.86~g~H_2O[/tex]
I hope it helps!