Question

PLS HELP

Simplify the function f(x) =
3x
(81)
4
Then determine the key aspects of the function.
The initial value is
The simplified base is
The domain is
The range is

Answer 1

Answer:

Step-by-step explanation:

This follows the form

$y=a(b)^x$

where a is the initial value and b is the base with the exponent.  Using that information, we can see that the initial value in our function is 1/3. Simplifying the base will take some work. Let's first rewrite this is a radical:

$81^{\frac{3x}{4} }=\sqrt[4]{81^{3x} }$

Now let's break up 81 into its factors. 81 is 9*9 which is 3*3*3*3.  Therefore,

$81=3^4$

We will use that as a simplification:

$\sqrt[4]{(3^4)^{3x}}$  which simplifies to

$\sqrt[4]{3^{12x}}$

Rewriting that as an exponent looks like this:

$3^{\frac{12x}{4}}$ which simplifies to

$3^{3x}$

That's the answer for the second part.  The whole exponential equation now is

$f(x)=\frac{1}{3}(3)^{3x}$

The domain for an exponential function is all real numbers and the range is

y > 0

Answer 2

Answer:

1/3

27

all real numbers

y > 0

ON EDGE

Step-by-step explanation: