Answer: .3, .1, .5, .6, .5
Step-by-step explanation:
[tex]\large \dfrac{\text{quantity of shaded spaces}}{\text{Total spaces}}=\dfrac{3}{10}=\large\boxed{.3}\\\\\\\dfrac{\text{quantity of 5s}}{\text{Total spaces}}=\dfrac{1}{10}=\large\boxed{.1}\\\\\\\dfrac{\text{quantity of even numbers}}{\text{Total spaces}}=\dfrac{5}{10}=\large\boxed{.5}\\\\\\\dfrac{\text{Total - white spaces}}{\text{Total spaces}}=\dfrac{10-4}{10}=\large\boxed{.6}\\\\\\\dfrac{\text{white spaces + number of 7s}}{\text{Total spaces}}=\dfrac{4+1}{10}=\large\boxed{.5}\\[/tex]
