Respuesta :
Answer:
[tex] Min =120, Max= 150[/tex]
The first quartile can be calculated with this data:
130, 135, 140, 120, 130, 130
And the middle value is:
[tex] Q_1 = \frac{140+120}{2}=130[/tex]
The median is the value in the 6th position from the dataset ordered and we got:
[tex] Median= 135[/tex]
The third quartile can be calculated with this data:
135 140 140 143 144 150
And the middle value is:
[tex] Q_3 = \frac{140+143}{2}=141.5[/tex]
The five number summary for this case:
Min. 1st Qu. Median Mean 3rd Qu. Max.
120.0 130.0 135.0 135.6 141.5 150.0
The boxplot is on the figure attached
Step-by-step explanation:
We have the following data given:
130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150
If we sort the values on increasing order we got:
120 130 130 130 130 135 140 140 143 144 150
The minimum and maximum are:
[tex] Min =120, Max= 150[/tex]
The first quartile can be calculated with this data:
130, 135, 140, 120, 130, 130
And the middle value is:
[tex] Q_1 = \frac{140+120}{2}=130[/tex]
The median is the value in the 6th position from the dataset ordered and we got:
[tex] Median= 135[/tex]
The third quartile can be calculated with this data:
135 140 140 143 144 150
And the middle value is:
[tex] Q_3 = \frac{140+143}{2}=141.5[/tex]
The five number summary for this case:
Min. 1st Qu. Median Mean 3rd Qu. Max.
120.0 130.0 135.0 135.6 141.5 150.0
The boxplot is on the figure attached
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