Question

CAN YOU HELP ME PLSSSS +40P A container with a volume of 3 liters contains a gas at 27°C and 2 atmospheric pressure. Find the work this gas does during the following operations. a) Its temperature is increased 5 times in constant volume b) Its volume is increased 4 times in constant pressure from the beginning. c) Its volume is doubled from the beginning.

Answer 1

Explanation:

main equation we need is

$\frac{pv}{t} = \frac{pv}{t}$

for Work done the equation is

W = P . ∆V (for isobar or constant pressure and isovolume or constant volume)

W = nRT ln V2/V1 (for isothermal or constant temperature)

p = pressure

v = volume

t = temperature (in Kelvin)

w = work

t = 27° C = 300 K

a. constant volume means ∆V (change on volume) is 0. So the work done in this process is 0

b. constant pressure (using SI unit)

W = P . ∆V = 2 . 1.01 . 10⁵ Pa . (12 - 3) . 10-³ m³ = 1 818 Joule

c. it's not clear in what operation in this process. but we can assume the process same with b (because if we will use constant temperature, there isn't any number for mol n) so

W = P . ∆V = 2 . 1.01 . 10⁵ Pa . (6 - 3) . 10-³ m³ = 606 Joule

hope this can help you