Question

In a titration experiment, a 10.00 ml sample of H2SO4 was titrated with 33.25 mL of 0.777 M KOH.
Calculate (H2SO4).

Answer 1

Answer:

H2SO4 = 0.3885 mol L-1

Explanation:

We need (i) a stoichiometric equation:

H2SO4 + 2NaOH = NaSO4 +2H2O

1:2

And (ii) equivalent quantities of sodium hydroxide

Moles of NaOH  = 10x $10^{-3}$L x 0.777mol $L^{-1}$ = 0.00777 mol

So H2SO4  = (0.5 x 0.00777 mol) / 0.001

= 0.3885 mol L-1