Respuesta :
Answer:
B
Explanation:
CH4 + O2 →H2O + CO2
Left side
C = 1
H = 4
O = 2
Right side
C = 1
H = 2
O = 3
So find common denominator in this case would be 6 O
CH4 + 3O2 →2H2O + CO2
Left side
C = 1
H = 4
O = 6
Right side
C = 1
H = 4
O = 6
Answer:
[tex]\huge \boxed{\mathrm{C) \ 1, 2,2,1}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O[/tex]
Balancing the Hydrogen atoms on the right side,
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O[/tex]
Balancing the Oxygen atoms on the left side,
[tex]\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O[/tex]
[tex]\rule[225]{225}{2}[/tex]