Answer: Molar Concentration of the solution is 3.475M
Explanation:
In order to calculate Molarity from Molality we must clarify its meaning
- Molarity (M) = mol solute / L of solution
- Molality (m) = mol solute / mass (in kg) of the solvent
In this case, we were giving the Molality (m)= 3.97 moles H2SO4/ 1 Kg of H20.
When calculating Molarity (M), we need moles of solute that is already contained in the molality and we need Liters of solution that we can calculate like this:
- Mass of any solution = mass solute + mass solvent
- Mass of any solution = (our case, we use 3.97 moles H2SO4 and using molar mass , we get the mass of the H2SO4) + Mass solvent : We already have it (1Kg H20 =1000g H2O)
Now, let´s calculate the mass solute,:
3.97moles H2SO4 x (98.08g H2SO4 /1mol H2SO4) = 389.4g H2SO4
- Mass of our solution = 389.4g H2SO4 + 1000Kg H20
- Mass of our solution = 1389.4 g Solution
When having the mass of the solution, now we can use the density of the solution to discovery the volumen of the solution.
- 1389.4 g Solution x ( 1mL solution / 1.216g solution)= 1142.6mL solution = 1.1426L solution
Finally, we have the correct values for calculating our molar concentration.
- Molarity (M) = mol solute / L of solution
- Molarity (M) H2SO4= 3.97moles / 1.1426 L solution = 3.475M
