Respuesta :
3 % = 0.003 : 12 = 0.0025
175 · ( 1 + 0.0025 )^(12 x) = 3,000
175 · (1.0025)^(12 x) = 3,000
1.0025^(12 x ) = 17.142857
[tex]12 x = log _{1.0025} 17.142857 [/tex]
12 x = 1138.0524
x = 1138.0524 : 12
x = 94.8377
Answer: D ) 94.8377 years
175 · ( 1 + 0.0025 )^(12 x) = 3,000
175 · (1.0025)^(12 x) = 3,000
1.0025^(12 x ) = 17.142857
[tex]12 x = log _{1.0025} 17.142857 [/tex]
12 x = 1138.0524
x = 1138.0524 : 12
x = 94.8377
Answer: D ) 94.8377 years
The correct answer is:
94.8377 years
Explanation:
The formula for compound interest is
[tex] A=p(1+\frac{r}{n})^{nt} [/tex], where A is the total amount, p is the amount of principal deposited, r is the interest rate as a decimal number, n is the number of times per year the interest is compounded, and t is the number of years.
For our problem, A = 3000; p = 175; r = 3% = 3/100 = 0.03; n = 12; and t is unknown:
[tex] 3000=175(1+\frac{0.03}{12})^{12t}
\\3000=175(1+0.0025)^{12t}
\\3000=175(1.0025)^{12t} [/tex]
Divide both sides by 175:
[tex] \frac{3000}{175}=\frac{175(1.0025)^{12t}}{175}
\\
\\\frac{120}{7}=1.0025^{12t} [/tex]
We will use logarithms to solve this. The base of the exponent is 1.0025, so this will be the base of the log:
[tex] \log_{1.0025}(\frac{120}{7})=12t [/tex]
Divide both sides by 12:
[tex] \frac{\log_{1.0025}(\frac{120}{7})}{12}=\frac{12t}{12}
\\
\\94.8377 [/tex]