Respuesta :
Answer:
THE SPECIFIC HEAT CAPACITY OF THE ALUMINIUM CAN IS 0.03747 J/g K
Explanation:
Heat liberated (Q) = MCΔT
Heat = 106.8 J
M = mass = 10 g
ΔT = 12°C= 12 + 273 K = 285 K
C = specific heat capacity = unknown
At a rise in 12 °C temperature, the aluminium can possesses a specific heat capacity of =
C = Q / MΔT
C = 106.8 J / 10 g * 285 K
C = 106.8 J / 2850 g K
C = 0.03747 J/g K
The specific heat capacity of the aluminum can weighing 10 g and absorbs 106.8 J of heat after been warmed to 12°C is 0.03747 J/ g K
Answer:
The specific heat of the aluminium can is 0.89 J/g°C
Explanation:
Step 1: Data given
Mass of the aluminium can = 10.0 grams
The amount of energy absorbed = 106.8 J
The temperature rises 12.0 °C
Step 2: Calculate the specific heat of the aluminium can
Q = m*c* ΔT
⇒with Q = the heat absorbed = 106.8 J
⇒with m = the mass of the aluminium can = 10.0 grams
⇒with c = the specific heat of the aluminium can = TO BE DETERMINED
⇒with ΔT = the rise of the temperature = 1.0°C
106.8 J = 10.0 grams * C * 12.0 °C
C = 106.8 J / (10.0 grams * 12.0 °C)
C = 0.89 J/g°C
The specific heat of the aluminium can is 0.89 J/g°C
