Question

2) Rearrange the Pythagorean Theorem to solve first for c and then y.

Answer 1

Answer:

$x=z-\sqrt{-y} , or, x^2=z^2-y^2\\y=z-\sqrt{-x}, or, y^2=z^2-x^2$

Step-by-step explanation:

I can't do much except put the Pythagorean theorem in terms of y or x.

All I did was isolate x or y by subtracting the, x or y variable from each side.

$-(y^2)+x^2 +y^2=z^2-(x^2)\\-(y^2)+x^2 +y^2=z^2-(y^2)$

Which tuns it into:

$x^2=z^2-y^2\\y^2=z^2-x^2$

And I isolated further by squaring each side, but squaring negative number is difficult and causes imaginary numbers so I just think it should stay as all of them to the power of two.