Given ΔADC and ΔAEB, What is AE?
![Given ΔADC and ΔAEB What is AE class=](https://us-static.z-dn.net/files/d34/bcf3d3ebbbc2943e37e563d2f1a7fa10.png)
Answer:
As shown in picture,
EB is perpendicular with AC
DC is perpendicular with AC
=> EB // DC
Applying Thales theorem:
BC/AC = ED/AD
=> AD = ED x AC/BC = 72 x 88/55 = 115.2
=> AE = AD - ED = 115.2 - 72 = 43.2
Hope this helps!
:)