Find the total surface area of this prism where the cross-section is an isosceles triangle.
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Answer:
620 cm2
Step-by-step explanation:
The base of the prism is a rectangle with 24 cm x 10 cm, so the base area is:
B = 24 * 10 = 240 cm2
The cross section is a triangle with base = 24 cm and height = 5 cm, so its area is:
C = 24 * 5 / 2 = 60 cm2
The sides are rectangles with 10 cm x 13 cm, so their area is:
D = 10 * 13 = 130 cm2
The total surface area is:
S = B + 2C + 2D = 240 + 2*60 + 2*130 = 620 cm2