Question

1. Chromium metal is reacted with 40.0mL of 3.0M tin (IV) chloride in the following reaction:
4Cr + 3SnCl4 --> 4CrCl3 + 3Sn
How many grams of tin will be produced? (3 marks) Please upload your work.
(Non-anonymous question )

Answer 1

Answer:

14.2 g

Explanation:

40.00 mL = 0.04000 L solution of SnCl4

3.0 M = 3.0 mol/L Molarity of solution of SnCl4

3.0 mol/L * 0.04000 L = 0.12 mol SnCl4

                          4Cr + 3SnCl4 --> 4CrCl3 + 3Sn

from reaction               3 mol                         3 mol

given                            0.12 mol                   x mol

x = 0.12 mol Sn

Molar mass (Sn) =118.71 g/mol

0.12 mol Sn * 118.71 g/mol≈ 14.2 g