rathburnrebecca01 rathburnrebecca01

31-05-2020
Mathematics

contestada

Find two consecutive odd integers such that the sum of their squares is 202.

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sofialynch365 sofialynch365

31-05-2020

Answer:

9 and 11

Step-by-step explanation:

The squareroot of 202 is 14... so the numbers are both less than 14.

9*9= 81

11*11= 121

121+81= 202

Answer Link

22stolc 22stolc

31-05-2020

Answer:

9 and 11

Step-by-step explanation:

(9^2) + (11^2) Simplify the exponents

81 + 121 = 202

Answer Link

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