Answer:
Step-by-step explanation:
Here the "common ratio" is 0.70. At the end of the first year the car will be worth 0.70 times its original value; let's call that w1. At the end of the second year the value will be 0.70*w1. And so on. The value continues to drop year by year, nearing but not equalling zero.
This type of function is a "decaying exponential."
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The value of function will continue to drop year by year, nearing but not equal to zero .
In mathematics, exponential decay describes the process of reducing an amount by a consistent percentage rate over a period of time. It can be expressed by the formula y=a(1-b)x wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.
According to question
f(x) = 18200 * (0.70) ^ 2
Represents the values of a certain type of car years
and decay rate is 70% or 0.70 which is common for each year
At the end of the first year the car will be worth 0.70 times its original value; let's call that w1.
At the end of the second year the value will be 0.70*w1. And so on.
Hence, The value of function will continue to drop year by year, nearing but not equal to zero because of decaying exponential
To know more about decaying exponential here :
https://brainly.com/question/27492127
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