A group of boys wanted to buy a basketball. If each boy were to contribute $8, then they would be $2 short. If they were to contribute $9 each, they would have an extra $4. How many boys were there and what was the price of the basketball?

Respuesta :

Answer:

Number of boys = 6

Price of basketball = [tex]\$50[/tex]

Explanation:

Given: If each boy were to contribute $8, then they would be $2 short. If they were to contribute $9 each, they would have an extra $4.

To find: Number of boys and the price of the basketball

Solution:

Let x denotes number of boys and y denotes the price of the basketball

If each boy were to contribute $8, then they would be $2 short, equation obtained is [tex]8x=y-2[/tex]

[tex]8x-y=-2\,\,(i)[/tex]

If they were to contribute $9 each, they would have an extra $4, equation obtained is [tex]9x=y+4[/tex]

[tex]9x-y=4\,\,(ii)[/tex]

Subtract equation (ii) from (i)

[tex](8x-y)-(9x-y)=-2-4\\-x=-6\\x=6[/tex]

Put [tex]x=6[/tex] in equation (i)

[tex]8(6)-y=-2\\48-y=-2\\y=48+2\\y=50[/tex]

So,

Number of boys = 6

Price of basketball = [tex]\$50[/tex]

Answer:

there are 6 boys and each basket ball costs 50$

Explanation:

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