Answer:
[tex]a^2+b^2-c^2+2ab[/tex]
Step-by-step explanation:
[tex](a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab[/tex]
Hope this helps!
a²+b²-c²+2ab
(x-y)(x+y)=x²-y²
[(a + b) - c ][(a + b) + c )=
=(a+b)²-c²
=a²+2ab+b²-c²
=a²+b²-c²+2ab
