Firm 1 produces output X with a cost function C_1(X)=\frac{X^2}{200}. Firm 2 produces output Y with a cost function C_2(X,Y)=\frac{Y^2}{100}-2X. Both firms face competitive markets. The competitive price of X is 6 and the competitive price of Y is \$ 5. There is no entry or exit into this market. What is the socially optimal production of X?

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Answer:

800

Explanation:

The objective here is to determine the socially optimal production of X.

For this to occur ; it is crucial that both firm must merge together.

Therefore; the Profit will be = Total revenue - Total Cost

From the question; the total revenue = 6X + 5Y ;     &

The total cost is : [tex]\dfrac{X^2}{200} + \dfrac{Y^2}{100} - 2X[/tex]

Now: The profit = [tex]6X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}-2X[/tex]

= [tex]8X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}[/tex]

If the socially optimal production of X is the differential of the equation [tex]8X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}[/tex]

(X) = [tex]8-\frac{2X}{200} =0[/tex]

= [tex]8-\frac{X}{100} =0[/tex]

= [tex]\dfrac{X}{100}=8[/tex]

= 800

Thus the social optimal production of X = 800

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