Answer:
800
Explanation:
The objective here is to determine the socially optimal production of X.
For this to occur ; it is crucial that both firm must merge together.
Therefore; the Profit will be = Total revenue - Total Cost
From the question; the total revenue = 6X + 5Y ; &
The total cost is : [tex]\dfrac{X^2}{200} + \dfrac{Y^2}{100} - 2X[/tex]
Now: The profit = [tex]6X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}-2X[/tex]
= [tex]8X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}[/tex]
If the socially optimal production of X is the differential of the equation [tex]8X+5Y - \dfrac{X^2}{200}- \dfrac{Y^2}{100}[/tex]
(X) = [tex]8-\frac{2X}{200} =0[/tex]
= [tex]8-\frac{X}{100} =0[/tex]
= [tex]\dfrac{X}{100}=8[/tex]
= 800
Thus the social optimal production of X = 800