Question

PLEASE HELP ME!!!

I have 5 pinks, 4 yellow, 3 orange, and 3 red starbursts. What is the probability that I will randomly pick a yellow starburst, put it back in the bag, and then randomly pick an orange starburst?

A. 7/15

B. 4/75

C. 4/15

D. 3/15

Answer 1

Answer:

B. 4/75

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

For each trial:

The probabilities of picking each startbust are the same, so each event is independent.

Independent events:

Two events, A and B, we have that:

$P(A \cap B) = P(A) \times P(B)$

In this question:

Event A: Yellow starburst on the first trial.

Event B: Orange starbust on the second trial.

4 yellow out of 5+4+3+3 = 15 starbursts.

This means that $P(A) = \frac{4}{15}$

3 orange out of 15 starbursts.

This means that $P(B) = \frac{3}{15}$

Probability of A, then B:

$P(A \cap B) = P(A) \times P(B) = \frac{4}{15} \times \frac{3}{15} = \frac{4*3}{15*15} = \frac{4}{15*5} = \frac{4}{75}$

So the correct answer is:

B. 4/75