Answer:
∠NQR, ∠NRQ and side QR for ΔQNR is equivalent to ∠MRQ, ∠MQR and side QR, which defines the two triangles and proves that the two triangles are congruent
Step-by-step explanation:
Here, we have
ΔPQR is an isosceles triangle,
∠MRQ = ∠NQR
Therefore, since ∡R = ∡Q (Base angles of isosceles ΔPQR), then;
∠MRQ + ∡Q + ∠QMR = 180° = ∠NQR + ∡R + ∠RNQ (Sum of angles in a triangle)
Whereby ∠MRQ = ∠NQR and ∡R = ∡Q, we have;
∠MRQ + ∡Q = ∠NQR + ∡R which gives;
∠QMR = ∠RNQ
Which gives;
∠NQR, ∠NRQ and side QR for ΔQNR is equivalent to ∠MRQ, ∠MQR and side QR, which defines the two triangles and proves that the two triangles are congruent.