Question

which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)

Answer 1

Answer:

y = -2/3x - 3

Step-by-step explanation:

y = mx + b

m = slope

(-3,-1) = (x,y)

Plus in the coordinates

-1 = -2/3(-3) + b

negative times negative = positive

-2/3 * -3 = 2

-1 = 2 +b

Use inverse operations

-2 --2

-3 = b

y = -2/3x - 3

Answer 2

Answer:

y = -2/3 x - 3

Step-by-step explanation:

since you have a point and a slope, you can use point - slope form

$y - y_{1} = m (x - x_{1} )$   plug in the point as $(x_{1}, y_{1})$ and the slope as m

y - (-1) = -2/3(x - (-3))      change two negatives into positive

y + 1 = -2/3 (x+3)            distribute the -2/3

y + 1 = -2/3x - 2              subtract 1 from both sides

y     = -2/3 x -3