Question

If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.

Answer 1

Answer:

$\dfrac{1}{6}$.

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : $S=\{1,2,3,4,5,6\}$

Number is greater than 3 : $A=\{4,5,6\}$

Number is odd : $A=\{1,3,5\}$

Number greater than 3 and an odd number : $A\cap B=\{5\}$

It is conclude that,

$n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1$

The probability of getting a number greater than 3 and an odd number is

$P=\dfrac{n(A\cap B)}{n(S)}$

$P=\dfrac{1}{6}$

Therefore, the required probability is $\dfrac{1}{6}$.

Answer 2

The probability of getting a number greater than 3 and an odd number is 5/6

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome

If a die is rolled one time, the sample space will be S = {1, 2, 3, 4, 5, 6}. The total outcome is 6

If a number greater than 3 and an odd number is rolled, the events will be E = {4, 5, 6, 1, 3}. The expected outcome will be 5

The probability of getting a number greater than 3 and an odd number is 5/6

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