Question

A spinner is divided into ten numbered sections, as shown.
(Assume the arrow never lands on a dividing line.)
With only one spin, what is the probability that the arrow
lands on an unshaded section or points to an even number?

Answer 1

Answer:

The probability the spinner has to fall into an unshaded section or point to an even number is: 5/10 or 1/2

Step-by-step explanation:

To understand this answer we need to analyze the context. First of all, spinners usually are numbered from 1 to 10. Meaning that they have 5 even numbers and 5 odd numbers. Because 2,4,6,8,10 are even numbers and 1,3,5,7,9, are odd numbers considering even numbers can be cut in half to obtain complete numbers. Now, if there are 5 out of 10 we have a probability of getting 5/10 chances of an even number or unshaded section. Simplified to 1/2.

Answer 2

C

unshaded section or an even number. there's 5 spaces and 3 that match your description so your answer is going to be c or 3/5