Question

The perpendicular bisector of chord AB is y=-2x+8, and the perpendicular bisector of chord BC is y= 3x-2. Recall the properties of chords. How can these equations be used to find the center of the circle that represents the whole plate

Answer 1

Answer:

We equate the two expressions since they both pass through the center of the circle.

The coordinate of the center of the circle is (2,4)

Step-by-step explanation:

From circle theorem, we know that the perpendicular bisector of a chord passes through the center of the circle.

Since both equations would pass through the center of the circle, we equate them.

So, -2x+8 = 3x-2

Solving for x, we have

3x + 2x = 8 + 2

5x = 10

x = 10/5

x = 2

Substituting x = 2 into any of the equations, we find the y- coordinate of the center of the circle.

y = -2x + 8 = -2(2) + 8 = -4 + 8 = 4

So, the coordinate of the center of the circle is (2,4)

Answer 2

Personal Answer:

The perpendicular bisector of a chord passes through the center of the circle/plate, meaning that both expressions can contribute to the finding the center. By solving for x and y, one can find the coordinates of the center of the circle.

Plato Sample Answer:

Because the perpendicular bisector of any chord of a circle passes though the center of the circle, these two perpendicular bisectors intersect at that point. You can set up a system of equations and solve to find the coordinates of the center.

I hope this helps!