Respuesta :
Answer:
[tex]z=\frac{0.923-0.631}{\sqrt{0.759(1-0.759)(\frac{1}{840}+\frac{1}{1077})}}=14.83[/tex]
The p value for this case would be:
[tex]p_v =2*P(Z>14.83)\approx 0[/tex]
For this case the p value is very low so we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of employment levels for men compared to woman were different
Step-by-step explanation:
Information given
[tex]X_{1}=775[/tex] represent the number of people fully employed men
[tex]X_{2}=680[/tex] represent the number of people fully employed women
[tex]n_{1}=840[/tex] sample 1 selected
[tex]n_{2}=1077[/tex] sample 2 selected
[tex]p_{1}=\frac{775}{840}=0.923[/tex] represent the proportion estimated for male employed
[tex]p_{2}=\frac{680}{1077}=0.631[/tex] represent the proportion estimated for women employed
[tex]\hat p[/tex] represent the pooled estimate of p
z would represent the statistic
[tex]p_v[/tex] represent the value for the test
System of hypothesis
We want to test the claim that the employment levels for men compared to woman were different, the system of hypothesis would be:
Null hypothesis:[tex]p_{1} = p_{2}[/tex]
Alternative hypothesis:[tex]p_{1} \neq p_{2}[/tex]
For this case the statistic is given by:
[tex]z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}[/tex] (1)
Where [tex]\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{775+680}{840+1077}=0.759[/tex]
Replacing the info given we got:
[tex]z=\frac{0.923-0.631}{\sqrt{0.759(1-0.759)(\frac{1}{840}+\frac{1}{1077})}}=14.83[/tex]
The p value for this case would be:
[tex]p_v =2*P(Z>14.83)\approx 0[/tex]
For this case the p value is very low so we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of employment levels for men compared to woman were different.