Def sum_divisors(n): sum =1 # Return the sum of all divisors of n, not including n x=int(n**0.5) for i in range(2,(x//1)+1): if n%i==0: sum=sum+i if n%i==0 and n/i!=i: sum=sum+(n/i) return sum print(sum_divisors(0)) # 0 print(sum_divisors(3)) # Should sum of 1 # 1 print(sum_divisors(36)) # Should sum of 1+2+3+4+6+9+12+18 # 55 print(sum_divisors(102)) # Should be sum of 2+3+6+17+34+51 # 114

Respuesta :

Answer:

This is a python program that counts the number of divisors of a given number and calculates the sum of the divisors.

Explanation:

The first line defines a function "sum_divisors" with an argument "n". The square root of the argument is converted to integer and assigned to the variable "x", then a for loop is used to iterate through the range 2 to the calculated nth number of divisors in the argument.The return keyword returns the sum value.

The function is called with several arguments and printed with the print function.

ACCESS MORE
EDU ACCESS