Question

The initial number of bacteria in the dish was 1,150. The amount of bacteria doubles at the end of each hour. Write a function b(t) that would represent this relationship after t hours. Use this function to determine how many bacteria would be in the dish after 10 hours and write it only as a number without units.

Answer 1

Answer:

$B(t) = 1150*(2)^{t}$

After 10 hours: 1,177,600

Step-by-step explanation:

The number of bacteria after b hours is given by the following equation:

$B(t) = B(0)(1+r)^{t}$

In which B(0) is the initial number of bacteria and r is the rate that it increases.

The initial number of bacteria in the dish was 1,150. The amount of bacteria doubles at the end of each hour.

This means that $B(0) = 1150, B(1) = 2*1150$

So

$B(t) = B(0)(1+r)^{t}$

$2*1150 = 1150(1+r)^{1}$

$1 + r = 2$

$r = 1$

So

$B(t) = 1150*(2)^{t}$

After 10 hours:

$B(10) = 1150*(2)^{10} = 1177600$

1,177,600 bacteria after 10 hours.