Answer:
[tex]=\frac{x^2-5}{4x+1}[/tex]
B is the correct answer
Step-by-step explanation:
[tex]f=4x+1,\:g=x^2-5,\:\left(\frac{g\left(x\right)}{f\left(x\right)}\right)\left(x\right)\\\mathrm{Assign\:the\:function}\:f=4x+1\\\\=\left(\frac{g\left(x\right)}{4x+1}\right)\left(x\right)\\\mathrm{Assign\:the\:function}\:g=x^2-5\\=\frac{x^2-5}{4x+1}[/tex]
