Question

10) Intravenous saline solutions have a concentration of 1.5 M NaCl. How many liters of saline can be prepared from 50.0 g of NaCl?

Answer 1

Answer:

0.57 mol/L

Explanation:

Molarity (M) is defined as the number of moles of solute per liter of solution (moles/Liter).

Molarity  =  $\frac{moles of solute}{liters of solution}$ or Moles  =  molarity × litres

so, the mass of Nacl in 1 mol is 58.44 g,

Moles of NaCl = 50.0g x 1 mole NaCl / 58.44 g

                          = 0.855 mol NaCl

Moles  =  molarity × litres

0.855 = 1.5 M x L

L = 0.57 mol/L

Hence, 0.57 mol/L can be prepared from 50.0 g of NaCl.