Question

A 125 g sample of strontium was heated from 0°C to 20°C. It absorbed 750 J of energy. What is the specific heat capacity of iron?

Answer 1

Answer:

Specific heat capacity of iron (C) = 0.3 J/GK

Explanation:

Given:

Mass of sample (m) = 125 gram

Change in heat (ΔT) = 20°C - 0°C = 20°C

Absorbed energy (ΔE) = 750 J

Find:

Specific heat capacity of iron (C) = ?

Computation:

⇒ Specific heat capacity of iron (C) = ΔE / [mΔT]

⇒ Specific heat capacity of iron (C) = 750 / [125 × 20]

⇒ Specific heat capacity of iron (C) = 750 / [2,500]

⇒ Specific heat capacity of iron (C) = 0.3 J/GK

Answer 2

Answer:

Specific heat capacity of iron (C) $= 0.3$ J/g°C

Explanation:

As we know that

Specific heat capacity of iron (C) $=\frac{\delta E}{ [m* \delta T]}$

Where $\delta E$ represents the change in the energy

m represents the mass of the sample and

$\delta T$ represents the change in temperature.

Given:

Mass of sample (m) $= 125$ gram

Change in heat ($\delta T$ ) $20 - 0 = 20$

Absorbed energy ($\delta E$)$= 750$ J

Substituting the given values in above equation, we get -

Specific heat capacity of iron (C)

$= \frac{750}{125*20}$

Specific heat capacity of iron (C) $= 0.3$ J/g°C