Question

Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divisible by 3. Who is correct, and why?

Sylvia is correct. Any variable term, when it is cubed, always has an exponent divisible by 3.
Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.
Sylvia is correct. In order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.
Miguel is correct. Sylvia confused the perfect square root with the perfect cube root.

Answer 1

Answer:

its B

Step-by-step explanation:

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Answer 2

Option B. is correct

What is a polynomial equation?

Polynomial equation are equation of number independent variables having relationship with dependent variable.

Since,
A monomial can have higher exponents so its exponents has probability to get divisible by 3 so when cube root for monomial performed.  
for example $\sqrt[3]{x^3}$ = x

Thus, Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.

Learn more about polynomial here:

brainly.com/question/11536910

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