Question

graph the circle x^2+y^2+2x+4y-44=0

Answer 1

Answer:

See explanation

Step-by-step explanation:

First, convert this to standard form. By completing the square, you can do the following:

$(x^2+2x+1)-1+(y^2+4y+4)-4-44=0$

$(x+1)^2+(y+2)^2=49$

This is a circle with center (-1,-2), and radius 7. It looks like the one I graphed below. Hope this helps!