Question

Eric, Cam, and Brooke are playing a game of mini golf on a computer. The computer program for the game stores

objects in terms of x and y coordinates. All coordinate values are in meters.

The players are shooting at the hole, which is located at (3,2). After hitting their initial shots, Eric's golf ball is at

(-6,6), Cam's golf ball is at (8,-6), and Brooke's golf ball is at (10,8).

If the player whose ball is farthest from the hole should shoot next, which player should shoot next?

Answer 1

Answer:

Eric

Step-by-step explanation:

First, we determine the distance of each player to the hole using the distance formula.

Given points $(x_1,y_1) and (x_2,y_2)$

Distance$=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Eric

The hole is at (3,2)

Eric's golf ball is at point (-6,6)

Distance=$\sqrt{(-6-3)^2+(6-2)^2}$

$=\sqrt{(-9)^2+(4)^2}\\=\sqrt{97} \\\approx 9.85$

Cam

The hole is at (3,2)

Cam's golf ball is at point (8,-6)

Distance=$\sqrt{(8-3)^2+(-6-2)^2}$

$=\sqrt{(5)^2+(-8)^2}\\=\sqrt{89} \approx9.43$

Brooke

The hole is at (3,2)

Brooke's golf ball is at point (10,8)

$Distance=\sqrt{(10-3)^2+(8-2)^2}\\=\sqrt{(7)^2+(6)^2}\\=\sqrt{85} \approx 9.22$

Since Eric's ball is the farthest from the hole, Eric should shoot next.

Answer 2

Answer: Erick

Step-by-step explanation: 9.85