Answer:
Step-by-step explanation:
Hello!
Inez walked in the treadmill for 7/10hr and had stopped for 1/2hr. How much time he was actually working out?
Time in the treadmill is [tex]\frac{7}{10}[/tex] hr
1 hour is the whole, you can express it as [tex]\frac{10}{10}[/tex].
If you express it in minutes then [tex]\frac{10}{10} = 60min[/tex], then [tex]\frac{1}{10} = \frac{60}{10}= 6 min[/tex]
Now you can calculate the amount of time he was on the treadmill:
[tex]\frac{7}{10}= 7*6= 42 min[/tex]
Time he had stopped
[tex]\frac{1}{2}= 30min[/tex]
Between the time he was on the treadmill and the time he rested, he worked out for 42 + 30= 72 min = 1 hour and 12 minutes.
During a 12- hour period, the temperature dropped 48 °C how many degrees did the temperature dropped each hour?
You can use cross multiplication to calculate how many degrees per hour the temperature decreased:
If in 12 hrs it decreased 48ºC
Then in 1 hr it decreased [tex]\frac{1*48}{12} = \\[/tex] 4ºC
The elevation of Turpan Pendi in China is -185 meters. The elevation of the Qattara Depression in Egypt is -163 meters. Compare the two elevations using < or >.______________
To easily determine which elevation is higher than the other you have to order them from least to greatest in a number line. These measurements are negative, which means that, the "higher" the module is, the less in the number line the negative value will be:
----|---------------------------------------|--------------------------------|--
-185 -163 0
(The line is not on scale)
Using < or >, you can say that -163 meters > -185 meters.
I hope this helps!
