A normal distribution has mean μ and standard deviation σ .An x-value is randomly selected from the distribution. Find P(μ−σ≤x≤μ+ 3σ)
P(μ−σ≤x≤μ+ 3σ)=

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Answer:

The probability that a randomly selected  x-value lies between μ − 2σ and μ is the  shaded area under the normal curve shown.  P(μ − 2σ ≤ x ≤ μ) = 0.135 + 0.34 = 0.475

Step-by-step explanation:

Correct Answer is 0.8385

Empirical Rule:

The Empirical Rule states that 99.7% of data observed following a normal distribution lies within 3 standard deviations of the mean. Under this rule, 68% of the data falls within one standard deviation, 95% within two standard deviations, and 99.7% within three standard deviations from the mean.

Here,

The 68-95-99.7 rule for the normal distribution says:

P(μ - σ ≤ x ≤ μ + σ) = 0.68

P(μ - 2σ ≤ x ≤ μ + 2σ) = 0.95

P(μ - 3σ ≤ x ≤ μ + 3σ) = 0.997

By taking the left half of the first interval and the right half of the last

interval, we have:

P(μ - σ ≤ x ≤ μ + 3σ) = 0.5*P(μ - σ ≤ x ≤ μ + σ) + 0.5*P(μ - 3σ ≤ x ≤ μ + 3σ) =

0.34 + 0.4985 = 0.8385

Learn more about Standard normal distribution here:

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