Answer:
81 has the most factors of 3
Step-by-step explanation:
To conclude which of the following options has the most factors of 3, take each of the number's prime factorization, which will help us solve the problem.
( 1 ) 81 is a composite number and is 9 squared. Knowing that 3 squared = 9, we can say that the prime factorization of 81 = 3 [tex]*[/tex] 3 [tex]*[/tex] 3 [tex]*[/tex] 3, which can also be denoted as 3⁴.
( 2 ) 270 is a composite number. The exponents in the prime factorization are 1, 3, and 1, and therefore it's prime factorization is - 3 [tex]*[/tex] 5 [tex]*[/tex] 3 [tex]*[/tex] 2 [tex]*[/tex] 3, composed of 3 3s.
( 3 ) If we put all of it together we have the factors 3 x 3 x 3 x 37 = 999. It can also be written in exponential form, with 3 to the power of 3 - hence having 3 factors of 3.
And finally the value 3333 has the prime factorization of 3 [tex]*[/tex] 11 [tex]*[/tex] 101, and as you can see it has 1 factor of 3. 81, having 4 factors of 3, is present with the most factors, and therefore is our solution.
Number 81 has the most number of factor 3. Option A is correct.
A number from the options to be determined that has the most number of factor 3.
factors can be defined by splitting the value into multipliable values.
Here,
Factors of 81 = 3,3,3,3 Number of factor 3 = 4
Factors of 270 =2,3,3,3,5 Number of factor 3 = 3
Factors of 999 =3,3,11 Number of factor 3 = 2
Factors of 3333 = 3,11 Number of factor 3 = 1
As per the above comparison, 81 has the most number of factor 3.
Thus, Number 81 has the most number of factors 3.
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