Question

A rectangle has a length of 9 millimeters and an area of 270 square millimeters.what is the width? what is the perimeter?​

Answer 1

Answer:

width-30

perimeter-78

Step-by-step explanation:

Since the area is length x width = area

You can do the same thing but backwards:

Area/length = width

now replace that with numbers

270/9 = 30 millimeters

now to make sure imagine a rectangle

it has a length of 9 millimeters and a width of 30 millimeters

how do you find the area?

length x width = area

9 x 30 = 270

now to find the perimeter

(length x 2) + (width x 2) = perimeter

(9 x 2) + (30 x 2) = ?

18 + 60 = 78

hope this helps :)

Answer 2

Required width is 30 millimeters & perimeter is 78 millimeters.

What is width of rectangle ?

Given, Length of rectangle(L) = 9 millimeters

Area of the rectangle = 270 square millimeters

We know that, area of rectangle = Length×Width = L×W

According to the problem,

L×W = 270

⇒ 9×W=270

⇒ W = 270/9

⇒ W = 30

So, Width of rectangle = 30 millimeters

What is perimeter of rectangle ?

Perimeter of rectangle = 2×(Length+Width)

                                      = 2×(L+W)

                                      = 2×(9+30)

                                      = 2×39

                                      = 78 millimeters

So, perimeter of rectangle = 78 millimeters

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